There exists a non-recursively enumerable subset of N which has a short description in terms of arithmetic

preprint OA: closed
Full text JSON View at publisher
Full text 2,945 characters · extracted from oa-doi-fallback · 2 sections · click to expand

Abstract

Let [\cdot] denote the integer part of the argument. We show that decision problems (1)-(3) are algorithmically undecidable when n∈N. (1) ∃p,q∈N ((n=2^p \cdot 3^q)∧∀(x_0,...,x_p)∈N^{p+1} ∃(y_0,...,y_p)∈{0,...,q}^{p+1} ∀i,j,k∈{0,...,p} (((x_j+1=x_k)⇒(y_j+1=y_k))∧((x_i \cdot x_j=x_k)⇒(y_i \cdot y_j=y_k)))). (2) ∀(x_0,...,x_{n−[\sqrt{n}]^2})∈N^{n+1−[\sqrt{n}]^2} ∃(y_0,...,y_{n−[\sqrt{n}]^2})∈{0,...,|n−[\sqrt{n}]^2−[\sqrt{n}]|}^{n+1-[\sqrt{n}]^2} ∀i,j,k∈{0,...,n−[\sqrt{n}]^2} (((x_j+1=x_k)⇒(y_j+1=y_k))∧((x_i \cdot x_j=x_k)⇒{y_i \cdot y_j=y_k))). (3) ∃(y_0,...,y_n)∈N^{n+1} ∀i,j,k∈{0,...,n} (((2^{2^{2^j \cdot 3^k}}+1 divides n) ⇒ (y_j+1=y_k))∧((2^{2^{2^i \cdot 3^j \cdot 5^{k+1}}}+1 divides n)⇒(y_i \cdot y_j=y_k))). We prove that the sets {n∈N: n satisfies condition (1)} and {n∈N: n satisfies condition (2)} are not recursively enumerable. We prove that the set {n ∈N: n does not satisfy condition (3)} is not recursively enumerable. For n∈N, let E_n={1=x_k, x_i+x_j=x_k, x_i \cdot x_j=x_k: i,j,k∈{0,...,n}}. For n∈N, f(n) denotes the smallest b∈N such that if a system of equations S⊆E_n has a solution in N^{n+1}, then S has a solution in {0,...,b}^{n+1}. The author proved earlier that the function f:N→N is computable in the limit and eventually dominates every computable function g:N→N. We present a short program in MuPAD which for n∈N prints the sequence {f_i(n)}_{i=0}^∞ of non-negative integers converging to f(n). For n∈N, β(n) denotes the smallest b∈N such that if a system of equations S⊆E_n has a unique solution in N^{n+1}, then this solution belongs to {0,...,b}^{n+1}. The author proved earlier that the function β:N→N is computable in the limit and eventually dominates every function δ:N→N with a single-fold Diophantine representation. We present a short program in MuPAD which for n∈N prints the sequence {β_i(n)}_{i=0}^∞ of non-negative integers converging to β(n). Supplementary Material File (a_tyszka_mar_16.pdf) - Download - 611.27 KB Information & Authors Information Version history Copyright This work is licensed under a Non Exclusive No Reuse License.

Keywords

Authors Metrics & Citations Metrics Article Usage 101views 37downloads Citations Download citation Apoloniusz Tyszka. There exists a non-recursively enumerable subset of N which has a short description in terms of arithmetic. Authorea. 17 March 2026. DOI: https://doi.org/10.22541/au.177377142.25850015/v1 DOI: https://doi.org/10.22541/au.177377142.25850015/v1 If you have the appropriate software installed, you can download article citation data to the citation manager of your choice. Simply select your manager software from the list below and click Download. For more information or tips please see 'Downloading to a citation manager' in the Help menu.

Text is read by the "Ask this paper" AI Q&A widget below. Extraction quality varies by source — PMC NXML preserves structure cleanly, OA-HTML may include some navigation residue, and OA-PDF can have broken hyphenation. The publisher copy (via DOI) is the canonical version.

My notes (saved in your browser only)

Ask this paper AI returns verbatim quotes from the full text · source: oa-doi-fallback

Answers must be backed by verbatim quotes from this paper's full text. Hallucinated quotes are dropped automatically; if no verbatim passage answers the question, we say so. How this works

Citation neighborhood (no data yet)

We don't have any in-corpus citations linked to this paper yet. This is a recent paper (2026) — citers typically take a year or two to land, and the OpenAlex reference graph may still be filling in.

Source provenance

europepmc
last seen: 2026-05-20T01:45:00.602351+00:00